CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Introduction to Trigonometry · Introduction to Trigonometry

Problem

Evaluate E=sin⁡(90∘−45∘)sec⁡30∘+cos⁡(90∘−30∘)csc⁡60∘E = \sin(90^\circ - 45^\circ)\sec 30^\circ + \cos(90^\circ - 30^\circ)\csc 60^\circ. (a) 6+34\dfrac{\sqrt{6}+\sqrt{3}}{4} (b) 6+33\dfrac{\sqrt{6}+3}{3} (c) 6+33\dfrac{\sqrt{6}+\sqrt{3}}{3} (d) 6−33\dfrac{\sqrt{6}-\sqrt{3}}{3}

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