Solid calcium carbonate (molar mass ) is added to of hydrochloric acid

CHEMISTRY · Subjective · A Level · Chemistry · Amount of substance · Amount of substance

Problem

Solid calcium carbonate (molar mass 100.1 g mol−1100.1\,\text{g\,mol}^{-1}) is added to 25.0 mL25.0\,\text{mL} of 0.500 M0.500\,\text{M} hydrochloric acid. The reaction proceeds in two steps: 1. CaCO3(s)+2 H+(aq)→Ca2+(aq)+H2CO3(aq)\mathrm{CaCO_3(s) + 2\,H^{+}(aq) \rightarrow Ca^{2+}(aq) + H_2CO_3(aq)} 2. H2CO3(aq)→CO2(g)+H2O(l)\mathrm{H_2CO_3(aq) \rightarrow CO_2(g) + H_2O(l)} Assuming the acid is the limiting reagent, calculate the maximum mass of CaCO3\mathrm{CaCO_3} (to three significant figures) that can be completely consumed.

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