If and are positive real numbers such that

MATHEMATICS · Single correct · CBSE · Mathematics · Sequences and Series · Sequences and Series

Problem

a

and

b

are positive real numbers such that

a + b = 6

, then the minimum value of

\left(\frac{4}{a} + \frac{1}{b}\right)

is equal to : (a)

\frac{2}{3}

(b)

\frac{1}{3}

\frac{3}{2}