Consider real numbers and such that and .

MATHEMATICS · Multi-part · CBSE · Mathematics · Inverse Trigonometric Functions · Inverse Trigonometric Functions

Problem

Consider real numbers xx and yy such that x, y∈[−1,1]x,\,y\in[-1,1] and x2+y2≤1x^{2}+y^{2}\le 1. (i) Prove that arcsin⁡x+arcsin⁡y=arcsin⁡(x1−y2+y1−x2).\arcsin x+\arcsin y=\arcsin\bigl(x\sqrt{1-y^{2}}+y\sqrt{1-x^{2}}\bigr). Clearly mention any domain restrictions required for the identity to hold in the principal value branch. (ii) Show that when x=513x=\dfrac{5}{13} and y=1213y=\dfrac{12}{13}, the right‐hand side of the identity in part (i) simplifies to π2\dfrac{\pi}{2}. (iii) Using the identity, evaluate arcsin⁡(513)+arcsin⁡(1213)\arcsin\left(\dfrac{5}{13}\right)+\arcsin\left(\dfrac{12}{13}\right) without a calculator.

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