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The locus of the image of the focus of the ellipse x^2 25 + y^2 9 = 1
MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections
Problem The locus of the image of the focus of the ellipse
x 2 25 + y 2 9 = 1 , with respect to any of the tangent to the ellipse \frac{x^2}{25} + \frac{y^2}{9} = 1, \text{ with respect to any of the tangent to the ellipse} 25 x 2 + 9 y 2 = 1 , with respect to any of the tangent to the ellipse
is
(1) ( x + 4 ) 2 + y 2 = 100 (x + 4)^2 + y^2 = 100 ( x + 4 ) 2 + y 2 = 100
(2) ( x + 2 ) 2 + y 2 = 50 (x + 2)^2 + y^2 = 50 ( x + 2 ) 2 + y 2 = 50
(3) ( x − 4 ) 2 + y 2 = 100 (x - 4)^2 + y^2 = 100 ( x − 4 ) 2 + y 2 = 100
(4) ( x − 2 ) 2 + y 2 = 50 (x - 2)^2 + y^2 = 50 ( x − 2 ) 2 + y 2 = 50
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