The locus of the image of the focus of the ellipse x^2 25 + y^2 9 = 1

MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

The locus of the image of the focus of the ellipse x225+y29=1, with respect to any of the tangent to the ellipse\frac{x^2}{25} + \frac{y^2}{9} = 1, \text{ with respect to any of the tangent to the ellipse} is (1) (x+4)2+y2=100(x + 4)^2 + y^2 = 100 (2) (x+2)2+y2=50(x + 2)^2 + y^2 = 50 (3) (x−4)2+y2=100(x - 4)^2 + y^2 = 100 (4) (x−2)2+y2=50(x - 2)^2 + y^2 = 50

Related theory

Browse the problem library