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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
e
2
x
+
log
x
d
x
=
\int e^{2x+\log x}\,dx=
∫
e
2
x
+
l
o
g
x
d
x
=
(a)
1
4
(
2
x
−
1
)
e
2
x
+
C
\frac{1}{4}(2x-1)e^{2x}+C
4
1
(
2
x
−
1
)
e
2
x
+
C
(b)
1
4
(
2
x
+
1
)
e
2
x
+
C
\frac{1}{4}(2x+1)e^{2x}+C
4
1
(
2
x
+
1
)
e
2
x
+
C
(c)
1
2
(
2
x
+
1
)
e
2
x
+
C
\frac{1}{2}(2x+1)e^{2x}+C
2
1
(
2
x
+
1
)
e
2
x
+
C
(d)
1
2
(
2
x
−
1
)
e
2
x
+
C
\frac{1}{2}(2x-1)e^{2x}+C
2
1
(
2
x
−
1
)
e
2
x
+
C
Related theory
Logarithmic Functions
Integration by Parts
Integration Techniques
Integrals
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