Evaluate the sum and hence determine the least positive integer for which the sum…

MATHEMATICS · Multi-part · CBSE · Mathematics · Arithmetic Progressions · Arithmetic Progressions

Problem

Evaluate the sum S(n)=∑k=1n(12−2k)S(n)=\displaystyle \sum_{k=1}^{n} \bigl(12 - 2k\bigr) and hence determine the least positive integer nn for which the sum becomes negative. (i) Obtain a simplified expression for S(n)S(n) in terms of nn. (ii) Using the result of part (i), find the smallest positive integer nn such that S(n)<0S(n) < 0.

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