CBSE

MATHEMATICS · Multi-part · CBSE · Mathematics · Inverse Trigonometric Functions · Inverse Trigonometric Functions

Problem

Consider

P=\arcsin\left(\dfrac{1}{3}\right)+\arcsin\left(\dfrac{2\sqrt{2}}{3}\right)

. (i) Show that

\sin P = 1

. (ii) Deduce the exact principal value of

P

. (iii) Hence evaluate

\arccos\left(\dfrac{1}{\sqrt{2}}\right)-P

, giving your answer in simplest exact form.

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