The locus of the midpoints of focal chords of the ellipse is:

MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

The locus of the midpoints of focal chords of the ellipse x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 is: (1) x2a2+y2b2=exa\frac{x^2}{a^2}+\frac{y^2}{b^2}=\frac{ex}{a} (2) x2a2−y2b2=exa\frac{x^2}{a^2}-\frac{y^2}{b^2}=\frac{ex}{a} (3) x2+y2=a2+b2x^2+y^2=a^2+b^2 (4) x2−y2=a2+b2x^2-y^2=a^2+b^2

Related theory

Browse the problem library