A block oscillating in simple harmonic motion is observed at to be at

PHYSICS · Subjective · A Level · Physics · Further mechanics and thermal physics · Further mechanics and thermal physics

Problem

A block oscillating in simple harmonic motion is observed at t=0t = 0 to be at x=+0.20 mx = +0.20\,\text{m}, moving towards the equilibrium position with speed 0.40 m s−10.40\,\text{m}\,\text{s}^{-1}. The amplitude of the motion is 0.50 m0.50\,\text{m}. a) Determine the angular frequency ω\omega of the oscillation. b) Find the earliest time after t=0t = 0 when the block will be at x=−0.20 mx = -0.20\,\text{m}. c) Calculate the time interval between the first and the second instants at which the magnitude of the displacement equals 0.20 m0.20\,\text{m}.

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