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MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections
Problem An ellipse has foci at ( ± 5 , 0 ) (\pm5,0) ( ± 5 , 0 ) P A + P B = 14 PA+PB=14 P A + P B = 14 x 2 25 + y 2 24 = 1 \displaystyle \frac{x^{2}}{25}+\frac{y^{2}}{24}=1 25 x 2 + 24 y 2 = 1 x 2 49 + y 2 24 = 1 \displaystyle \frac{x^{2}}{49}+\frac{y^{2}}{24}=1 49 x 2 + 24 y 2 = 1 x 2 49 − y 2 24 = 1 \displaystyle \frac{x^{2}}{49}-\frac{y^{2}}{24}=1 49 x 2 − 24 y 2 = 1 x 2 24 + y 2 49 = 1 \displaystyle \frac{x^{2}}{24}+\frac{y^{2}}{49}=1 24 x 2 + 49 y 2 = 1 Browse the problem library