In the equation above

MATHEMATICS · Single correct · CBSE · Mathematics · Quadratic Equations · Quadratic Equations

Problem

(t+1)^2+c=0

In the equation above,

c

is a constant. The equation has solutions at

t=\frac{3}{2}

and

t=-\frac{7}{2}

. What is the value of

c

? (A)

-\frac{729}{4}

(B)

-\frac{121}{4}

(C)

-\frac{25}{4}

(D)

-1