A three-step decay chain is A→B→C→ stable D. The half-lives are T1/2(A)=3h, T1/2(B)=30min and T1/2(C)=5min. At the instant t=0 there are 1.0×1018 atoms of A and none of B or C.
(a) Calculate the number of atoms of A, B and C present after 4h.
(b) Hence find the activity of C at t=4h.
(c) Determine the ratio of the activities of C to B at this time and comment on what this indicates about the stage reached in the decay sequence.