The value of is equal to

MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals

Problem

The value of

\int_{-\pi/2}^{\pi/2} \frac{x^2 \cos x}{1+e^x}\,dx

is equal to (1)

\frac{\pi^2}{4}-2

(2)

\frac{\pi^2}{4}+2

(3)

\pi^2-e^{-\pi/2}

(4)

\pi^2+e^{\pi/2}