A solution of ions and a solution of ions are each mixed with in separate beakers at

CHEMISTRY · Single correct · AP · Chemistry · Equilibrium · Equilibrium

Problem

A 0.010 M0.010\,\text{M} solution of Ba2+Ba^{2+} ions and a 0.010 M0.010\,\text{M} solution of Ag+Ag^{+} ions are each mixed with Na2SO4 (aq)Na_2SO_4\,(aq) in separate beakers at 25 ∘C25\,^\circ\text{C}. The relevant solubility product constants are Ksp(BaSO4)=1.1×10−10K_{sp}(\mathrm{BaSO_4}) = 1.1\times10^{-10} and Ksp(Ag2SO4)=1.2×10−5K_{sp}(\mathrm{Ag_2SO_4}) = 1.2\times10^{-5}. Which statement best predicts which solid will precipitate first as sulfate ions are gradually added? (a) Ag2SO4\mathrm{Ag_2SO_4} will precipitate before BaSO4\mathrm{BaSO_4} because its KspK_{sp} value is larger. (b) Both sulfates will begin to precipitate at the same sulfate concentration since the two solutions have identical 0.010 M0.010\,\text{M} cation concentrations. (c) BaSO4\mathrm{BaSO_4} will precipitate before Ag2SO4\mathrm{Ag_2SO_4} because it requires a much lower [SO42−][\mathrm{SO_4^{2-}}] to exceed KspK_{sp}. (d) No precipitate will form in either beaker because the sulfate concentration can never become great enough to surpass either KspK_{sp} value.

Related theory

Browse the problem library