For a continuous function

MATHEMATICS · Subjective · CBSE · Mathematics · Integrals · Integrals

Problem

For a continuous function hh, suppose ∫−42h(t) dt=9\displaystyle \int_{-4}^{2} h(t)\,dt = 9 and ∫−12h(t) dt=−3\displaystyle \int_{-1}^{2} h(t)\,dt = -3. Determine ∫−4−1h(t) dt\displaystyle \int_{-4}^{-1} h(t)\,dt.

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