Show that the middle term in the expansion of is 1 3 5 (2n-1) n! 2^n x^n

MATHEMATICS · Subjective · CBSE · Mathematics · Binomial Theorem · Binomial Theorem

Problem

Show that the middle term in the expansion of (1+x)2n(1+x)^{2n} is 1⋅3⋅5…(2n−1)n!⋅2nxn,n being a positive integer.\frac{1 \cdot 3 \cdot 5 \dots (2n-1)}{n!} \cdot 2^n x^n, n \text{ being a positive integer.}

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