A commonly cited induced fission reaction is The nuclear masses (in u) are provided…

PHYSICS · Multi-part · CBSE · Physics · Nuclei · Nuclei

Problem

A commonly cited induced fission reaction is 92235U+01n  ⟶  56141Ba+3692Kr+3 01n_{92}^{235}\text{U}+_{0}^{1}\text{n}\;\longrightarrow\;_{56}^{141}\text{Ba}+_{36}^{92}\text{Kr}+3\,_{0}^{1}\text{n} The nuclear masses (in u) are provided below: • m(92235U)=235.043930 um(_{92}^{235}\text{U}) = 235.043930\,\text{u} • m(56141Ba)=140.914411 um(_{56}^{141}\text{Ba}) = 140.914411\,\text{u} • m(3692Kr)=91.926156 um(_{36}^{92}\text{Kr}) = 91.926156\,\text{u} • m(01n)=1.008665 um(_{0}^{1}\text{n}) = 1.008665\,\text{u} Take 1 u=931.5 MeV/c21\,\text{u} = 931.5\,\text{MeV}/c^{2} and 1 MeV=1.602×10−13 J1\,\text{MeV} = 1.602\times10^{-13}\,\text{J}. (a) Calculate the total mass of the reactants and the total mass of the products. Hence determine the mass difference for the reaction. (b) Compute the energy released per fission event in MeV. (c) Express the energy found in part (b) in joules.

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