In the standard contradiction proof that is not rational

MATHEMATICS · Single correct · CBSE · Mathematics · Real Numbers · Real Numbers

Problem

In the standard contradiction proof that

\sqrt{2}

is not rational, which initial assumption is made? (a)

\sqrt{2}

can be written as

\dfrac{p}{q}

where

p

and

q

are odd integers. (b) The decimal expansion of

\sqrt{2}

is terminating. (c)

\sqrt{2}

can be written as

\dfrac{p}{q}

where

p

and

q

are coprime integers. (d)

\sqrt{2}

can be written as

\dfrac{p}{q}

where

p

and

q

are even integers.