In stellar interiors four hydrogen nuclei (protons) can fuse to form one 4He nucleus. Ignore the emission of any other particles and take the following nuclear masses:
mp=1.00727u, mass of 4He nucleus =4.00150u. Avogadro constant NA=6.022×1023mol−1, 1u=931.5MeV/c2.
(a) Calculate the mass defect for the fusion of four protons into one 4He nucleus.
(b) Determine the energy released per fusion event in MeV.
(c) Estimate the total energy released when 1.0g of hydrogen is completely converted into helium by this process.