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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
x
tan
−
1
x
(
1
+
x
2
)
3
/
2
d
x
=
\int\frac{x\tan^{-1}x}{(1+x^2)^{3/2}}\,dx=
∫
(
1
+
x
2
)
3/2
x
t
a
n
−
1
x
d
x
=
(a)
x
+
tan
−
1
x
1
+
x
2
+
C
\frac{x+\tan^{-1}x}{\sqrt{1+x^2}}+C
1
+
x
2
x
+
t
a
n
−
1
x
+
C
(b)
x
−
tan
−
1
x
1
+
x
2
+
C
\frac{x-\tan^{-1}x}{\sqrt{1+x^2}}+C
1
+
x
2
x
−
t
a
n
−
1
x
+
C
(c)
tan
−
1
x
−
x
1
+
x
2
+
C
\frac{\tan^{-1}x-x}{\sqrt{1+x^2}}+C
1
+
x
2
t
a
n
−
1
x
−
x
+
C
(d) None of these
Related theory
Integration by Parts
Integration Techniques
Integrals
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