Calcium fluoride, CaF2(s)

CHEMISTRY · Subjective · AP · Chemistry · Acids and Bases · Acids and Bases

Problem

Calcium fluoride, CaF2(s), has Ksp=3.9×10−11K_{sp}=3.9\times10^{-11} at 25 °C. The acid dissociation constant for hydrofluoric acid is Ka=6.6×10−4K_a=6.6\times10^{-4}. What pH must a solution have so that the molar solubility of CaF2 is exactly 1.0×10−3 M1.0\times10^{-3}\,\text{M}?

Related theory

Browse the problem library