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For the fusion reaction use the atomic masses given below to calculate the energy…
PHYSICS · Subjective · A Level · Physics · Nuclear physics · Nuclear physics
Problem For the fusion reaction
1 2 H + 1 3 H → 2 4 He + n ^2_1\text{H} + ^3_1\text{H} \to ^4_2\text{He} + n 1 2 H + 1 3 H → 2 4 He + n
use the atomic masses given below to calculate the energy released per reaction in MeV.
m ( 1 2 H ) = 2.014102 u , m ( 1 3 H ) = 3.016049 u , m ( 2 4 He ) = 4.002603 u , m ( n ) = 1.008665 u \begin{aligned}
\!m(^2_1\text{H})&=2.014102\,\text{u},\\
\!m(^3_1\text{H})&=3.016049\,\text{u},\\
\!m(^4_2\text{He})&=4.002603\,\text{u},\\
\!m(n)&=1.008665\,\text{u}
\end{aligned} m ( 1 2 H ) m ( 1 3 H ) m ( 2 4 He ) m ( n ) = 2.014102 u , = 3.016049 u , = 4.002603 u , = 1.008665 u
Take 1 u = 931.5 MeV / c 2 1\,\text{u} = 931.5\,\text{MeV}/c^{2} 1 u = 931.5 MeV / c 2 .
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