For the fusion reaction use the atomic masses given below to calculate the energy…

PHYSICS · Subjective · A Level · Physics · Nuclear physics · Nuclear physics

Problem

For the fusion reaction 12H+13H→24He+n^2_1\text{H} + ^3_1\text{H} \to ^4_2\text{He} + n use the atomic masses given below to calculate the energy released per reaction in MeV.  ⁣m(12H)=2.014102 u, ⁣m(13H)=3.016049 u, ⁣m(24He)=4.002603 u, ⁣m(n)=1.008665 u\begin{aligned} \!m(^2_1\text{H})&=2.014102\,\text{u},\\ \!m(^3_1\text{H})&=3.016049\,\text{u},\\ \!m(^4_2\text{He})&=4.002603\,\text{u},\\ \!m(n)&=1.008665\,\text{u} \end{aligned} Take 1 u=931.5 MeV/c21\,\text{u} = 931.5\,\text{MeV}/c^{2}.

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