A particle moves along a straight line so that its velocity (in meters per second) at…

MATHEMATICS · Multi-part · CBSE · Mathematics · Integrals · Integrals

Problem

A particle moves along a straight line so that its velocity (in meters per second) at time tt seconds is given by v(t)=6t2−4+3e−t.v(t)=6t^{2}-4+3e^{-t}. At time t=0t=0, the particle is 5 meters to the right of the origin. (a) Determine the particle’s position function s(t)s(t) for t≥0t\ge 0. Express your answer in simplest form. (b) Calculate the particle’s displacement (signed distance) during the first 2 seconds. (c) Is the total distance traveled during the first 2 seconds equal to the displacement you found in part (b)? Explain your reasoning without additional calculation.

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