The function is given by p(x)= cases 1, & 0 x<1, 2, & 1 x<2, 3-x, & 2 x 3

MATHEMATICS · Subjective · AP · Calculus AB · Integration and Accumulation of Change · Integration and Accumulation of Change

Problem

The function pp is given by p(x)={1,0≤x<1,2,1≤x<2,3−x,2≤x≤3.p(x)=\begin{cases}1, & 0\le x<1,\\ 2, & 1\le x<2,\\ 3-x, & 2\le x\le 3.\end{cases} Determine ∫03p(x) dx\int_{0}^{3} p(x)\,dx.

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