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Find the Binding energy per nucleon for
PHYSICS · Single correct · CBSE · Physics · Nuclei · Nuclei
Problem
Find the Binding energy per nucleon for
50
120
Sn
{}^{120}_{50}\text{Sn}
50
120
Sn
. Mass of proton
m
p
=
1.00783
U
m_p = 1.00783 \text{ U}
m
p
=
1.00783
U
, mass of neutron
m
n
=
1.00867
U
m_n = 1.00867 \text{ U}
m
n
=
1.00867
U
and mass of tin nucleus
m
Sn
=
119.902199
U
m_{\text{Sn}} = 119.902199 \text{ U}
m
Sn
=
119.902199
U
. (take
1
U
=
931
MeV
1 \text{ U} = 931 \text{ MeV}
1
U
=
931
MeV
) (1)
7.5
MeV
7.5 \text{ MeV}
7.5
MeV
(2)
9.0
MeV
9.0 \text{ MeV}
9.0
MeV
(3)
8.0
MeV
8.0 \text{ MeV}
8.0
MeV
(4)
8.5
MeV
8.5 \text{ MeV}
8.5
MeV
Related theory
Mass-Energy Equivalence
Nuclear Binding Energy
Mass defect and binding energy
Nuclear physics
Nuclei
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