During Searle's experiment

PHYSICS · Subjective · CBSE · Physics · Mechanical Properties of Solids · Mechanical Properties of Solids

Problem

During Searle's experiment, zero of the Vernier scale lies between 3.20×10−23.20 \times 10^{-2} m and 3.25×10−23.25 \times 10^{-2} m of the main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of 2 kg is applied to the wire, the zero of the Vernier scale still lies between 3.20×10−23.20 \times 10^{-2} m and 3.25×10−23.25 \times 10^{-2} m of the main scale but now the 45th division of Vernier scale coincides with one of the main scale divisions. The length of the thin metallic wire is 2 m and its cross-sectional area is 8×10−7 m28 \times 10^{-7} \text{ m}^2 . The least count of the Vernier scale is 1.0×10−51.0 \times 10^{-5} m. The maximum percentage error in the Young's modulus of the wire is [Adv. 2014]

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