Each deuterium–tritium fusion event releases 17.6 MeV

PHYSICS · Subjective · CBSE · Physics · Nuclei · Nuclei

Problem

Each deuterium–tritium fusion event releases 17.6 MeV. How many such fusion events are needed to obtain 5 MJ of energy? (Take

1\,\text{eV}=1.6\times10^{-19}\,\text{J}

.)

Related theory

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