For the differential equation with the initial condition

MATHEMATICS · Single correct · CBSE · Mathematics · Differential Equations · Differential Equations

Problem

For the differential equation dydx=sin⁡x+1\dfrac{dy}{dx}=\sin x+1 with the initial condition y(0)=4y(0)=4, determine the exact value of y ⁣(π2)y\!\left(\dfrac{\pi}{2}\right). (a) 4+π24+\dfrac{\pi}{2} (b) 6+π26+\dfrac{\pi}{2} (c) 5+π25+\dfrac{\pi}{2} (d) 3+π23+\dfrac{\pi}{2}

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