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For the differential equation with the initial condition
MATHEMATICS · Single correct · CBSE · Mathematics · Differential Equations · Differential Equations
Problem For the differential equation d y d x = sin x + 1 \dfrac{dy}{dx}=\sin x+1 d x d y = sin x + 1 with the initial condition y ( 0 ) = 4 y(0)=4 y ( 0 ) = 4 , determine the exact value of y ( π 2 ) y\!\left(\dfrac{\pi}{2}\right) y ( 2 π ) .
(a) 4 + π 2 4+\dfrac{\pi}{2} 4 + 2 π
(b) 6 + π 2 6+\dfrac{\pi}{2} 6 + 2 π
(c) 5 + π 2 5+\dfrac{\pi}{2} 5 + 2 π
(d) 3 + π 2 3+\dfrac{\pi}{2} 3 + 2 π
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