Upon mixing 45.0 mL of 0.25 M lead nitrate solution with 25 mL of 0.10*M* chromic sulphate
CHEMISTRY · Subjective · A Level · Chemistry · Amount of substance · Amount of substance
Problem
Upon mixing 45.0 mL of 0.25 *M* lead nitrate solution with 25 mL of 0.10*M* chromic sulphate, precipitation of lead sulphate takes place. How many mole of lead sulphate are formed? Also calculate the molar concentrations of the species left behind in final solution. Assume that lead sulphate is completely insoluble. (IIT 1993)