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The fusion reaction ^2_1 D + ^2_1 D ^3_2 He + n uses the following atomic masses: , ,
PHYSICS · Subjective · CBSE · Physics · Nuclei · Nuclei
Problem
The fusion reaction
1
2
D
+
1
2
D
→
2
3
H
e
+
n
^2_1\mathrm D + ^2_1\mathrm D \rightarrow ^3_2\mathrm{He} + n
1
2
D
+
1
2
D
→
2
3
He
+
n
uses the following atomic masses:
1
2
D
=
2.014102
u
^2_1\mathrm D = 2.014102\,\text{u}
1
2
D
=
2.014102
u
,
2
3
H
e
=
3.016029
u
^3_2\mathrm{He} = 3.016029\,\text{u}
2
3
He
=
3.016029
u
,
n
=
1.008665
u
n = 1.008665\,\text{u}
n
=
1.008665
u
. Calculate the energy released per fusion event. (Take
1
u
=
931
MeV
/
c
2
1\,\text{u} = 931\,\text{MeV}/c^{2}
1
u
=
931
MeV
/
c
2
.)
Related theory
Nuclear Binding Energy
Mass defect and binding energy
Nuclear physics
Mass energy equivalence
Nuclei
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