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If , then the value of…
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
If
2
f
(
x
)
+
f
(
−
x
)
=
1
x
sin
(
x
−
1
x
)
2f(x)+f(-x)=\dfrac{1}{x}\sin\!\left(x-\dfrac{1}{x}\right)
2
f
(
x
)
+
f
(
−
x
)
=
x
1
sin
(
x
−
x
1
)
, then the value of
∫
1
/
e
e
f
(
x
)
d
x
\int_{1/e}^{e}f(x)\,dx
∫
1/
e
e
f
(
x
)
d
x
is (1)
0
0
0
(2)
e
e
e
(3)
1
/
e
1/e
1/
e
(4)
e
+
1
/
e
e+1/e
e
+
1/
e
Related theory
Types of Functions
Functions
Properties of Definite Integrals
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Integrals
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