CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Inverse Trigonometric Functions · Inverse Trigonometric Functions

Problem

If cos⁡(2sin⁡−1x)=19\cos(2\sin^{-1}x)=\dfrac{1}{9}, then x=x= (a) Only 23\dfrac{2}{3} (b) Only −23-\dfrac{2}{3} (c) 23,−23\dfrac{2}{3},-\dfrac{2}{3} (d) Neither 23\dfrac{2}{3} nor −23-\dfrac{2}{3}

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