The value of

MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals

Problem

The value of I=dx(a+bx2)b−ax2I = \frac{dx}{(a+bx^2)\sqrt{b-ax^2}} , is (1) 1a(a2+b2)tan⁡−1(xa2+b2ab−ax2)+C\frac{1}{\sqrt{a(a^2+b^2)}} \tan^{-1} \left( \frac{x\sqrt{a^2+b^2}}{a\sqrt{b-ax^2}} \right) + C (2) 1(a2+b2)tan⁡−1(xa2+b2ab−ax2)+C\frac{1}{\sqrt{(a^2+b^2)}} \tan^{-1} \left( \frac{x\sqrt{a^2+b^2}}{a\sqrt{b-ax^2}} \right) + C (3) 1a(a2+b2)tan⁡−1(xa2+b2a)+C\frac{1}{\sqrt{a(a^2+b^2)}} \tan^{-1} \left( \frac{x\sqrt{a^2+b^2}}{a} \right) + C (4) None of the above

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