For a net force acts on a object according to the expression F_x(t)=F_0 ! ( t T )…

PHYSICS · Multi-part · AP · Physics 1: Algebra-based · Linear Momentum · Linear Momentum

Problem

For 0≤t≤T0\le t\le T a net force acts on a 0.20 kg0.20\text{ kg} object according to the expression Fx(t)=F0sin⁡ ⁣(πtT)F_x(t)=F_0\sin\!\left(\frac{\pi t}{T}\right) where F0=50 NF_0=50\text{ N} and T=0.10 sT=0.10\text{ s}. For t<0t<0 and t>Tt>T, the net horizontal force is zero. The object is initially at rest. (a) Derive an expression, in terms of F0F_0 and TT, for the total impulse delivered to the object during the interval 0≤t≤T0\le t\le T. (b) Using the given numerical values, calculate the numerical value of the impulse. (c) Determine the object’s speed immediately after t=Tt=T. (d) Suppose instead that the net force follows Fx(t)=F0sin⁡ ⁣(2πtT)F_x(t)=F_0\sin\!\left(\tfrac{2\pi t}{T}\right) for 0≤t≤T20\le t\le \tfrac{T}{2} and is zero afterward. Calculate the impulse in this modified case and state the percentage difference compared with the impulse found in part (b).

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