Steel ruptures when a shear of is applied

PHYSICS · Single correct · CBSE · Physics · Mechanical Properties of Solids · Mechanical Properties of Solids

Problem

Steel ruptures when a shear of

3.5 \times 10^8 \text{ N m}^{-2}

is applied. The force needed to punch a 1 cm diameter hole in a steel sheet 0.3 cm thick is nearly: (1)

1.4 \times 10^4 \text{ N}

(2)

2.7 \times 10^4 \text{ N}

(3)

3.3 \times 10^4 \text{ N}

(4)

1.1 \times 10^4 \text{ N}