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A mass attached to a spring (force constant ) executes simple harmonic motion of amplitude
PHYSICS · Single correct · CBSE · Physics · Oscillations · Oscillations
Problem
A
0.20
kg
0.20\,\text{kg}
0.20
kg
mass attached to a spring (force constant
80
N
m
−
1
80\,\text{N}\,\text{m}^{-1}
80
N
m
−
1
) executes simple harmonic motion of amplitude
0.10
m
0.10\,\text{m}
0.10
m
. Calculate its speed when its displacement from equilibrium is
0.06
m
0.06\,\text{m}
0.06
m
. (a)
1.2
m
s
−
1
1.2\,\text{m}\,\text{s}^{-1}
1.2
m
s
−
1
(b)
2.6
m
s
−
1
2.6\,\text{m}\,\text{s}^{-1}
2.6
m
s
−
1
(c)
1.6
m
s
−
1
1.6\,\text{m}\,\text{s}^{-1}
1.6
m
s
−
1
(d)
0.8
m
s
−
1
0.8\,\text{m}\,\text{s}^{-1}
0.8
m
s
−
1
Related theory
SHM Energy
SHM Kinematics
Simple harmonic motion
Oscillations
Velocity and acceleration in SHM
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