An alpha particle of energy 5 MeV is scattered through by a fixed uranium nucleus

PHYSICS · Single correct · CBSE · Physics · Atoms · Atoms

Problem

An alpha particle of energy 5 MeV is scattered through

180^\circ

by a fixed uranium nucleus. The distance of closest approach is of the order of (1) 1 Å (2)

10^{-10}

cm (3)

10^{-12}

cm (4)

10^{-15}