A horizontal force acting on a block of mass 0.50 kg is given by newton for

PHYSICS · Multi-part · CBSE · Physics · Laws of Motion · Laws of Motion

Problem

A horizontal force acting on a block of mass 0.50 kg is given by F(t)=100sin⁡ ⁣(πt0.050)F(t)=100\sin\!\bigl(\dfrac{\pi t}{0.050}\bigr) newton for 0≤t≤0.050 s0\le t\le0.050\,\text{s}. The block is initially at rest on a frictionless surface. (a) Calculate the impulse delivered to the block during this time interval. (b) Determine the speed of the block at t=0.050 st=0.050\,\text{s}.

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