The velocity of a simple harmonic oscillator is expressed as

PHYSICS · Single correct · CBSE · Physics · Oscillations · Oscillations

Problem

v = 0.40\sin(4\pi t)

, with v in meters per second and t in seconds. What is the maximum magnitude of the oscillator’s acceleration? (a)

2.5\,\text{m}\,\text{s}^{-2}

(b)

1.6\,\text{m}\,\text{s}^{-2}

(c)

5.0\,\text{m}\,\text{s}^{-2}

(d)

15.8\,\text{m}\,\text{s}^{-2}