The fusion reaction has the following atomic masses: Using

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Problem

The fusion reaction 2H+3H→4He+n^2\text{H}+^3\text{H}\rightarrow{}^4\text{He}+n has the following atomic masses: 2H:2.014102 u^2\text{H}: 2.014102\,\text{u} 3H:3.016049 u^3\text{H}: 3.016049\,\text{u} 4He:4.002603 u^4\text{He}: 4.002603\,\text{u} n:1.008665 un: 1.008665\,\text{u} Using 1 u=931 MeV/c21\,\text{u}=931\,\text{MeV}/c^{2}, calculate the energy Q released (to the nearest tenth of a MeV). (a) 1.9 MeV1.9\text{ MeV} (b) −17.6 MeV-17.6\text{ MeV} (c) 17.6 MeV17.6\text{ MeV} (d) 4.4 MeV4.4\text{ MeV}

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