The solubility product constant of at 25 °C is

CHEMISTRY · Single correct · AP · Chemistry · Equilibrium · Equilibrium

Problem

The solubility product constant of AgCl\text{AgCl} at 25 °C is Ksp=1.8×10−10K_{sp}=1.8\times10^{-10}. What is the molar solubility of AgCl\text{AgCl} in pure water at this temperature? (a) 1.3×10−4 M1.3\times10^{-4}\,\text{M} (b) 1.3×10−5 M1.3\times10^{-5}\,\text{M} (c) 6.7×10−6 M6.7\times10^{-6}\,\text{M} (d) 1.8×10−10 M1.8\times10^{-10}\,\text{M}

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