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If , then…
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
If
I
=
∫
e
−
x
log
(
e
x
+
1
)
d
x
I=\int e^{-x}\log(e^x+1)\,dx
I
=
∫
e
−
x
lo
g
(
e
x
+
1
)
d
x
, then
I
I
I
equals: (a)
x
+
(
e
−
x
+
1
)
log
(
e
x
+
1
)
+
C
x+(e^{-x}+1)\log(e^x+1)+C
x
+
(
e
−
x
+
1
)
lo
g
(
e
x
+
1
)
+
C
(b)
x
+
(
e
x
+
1
)
log
(
e
x
+
1
)
+
C
x+(e^x+1)\log(e^x+1)+C
x
+
(
e
x
+
1
)
lo
g
(
e
x
+
1
)
+
C
(c)
x
−
(
e
−
x
+
1
)
log
(
e
x
+
1
)
+
C
x-(e^{-x}+1)\log(e^x+1)+C
x
−
(
e
−
x
+
1
)
lo
g
(
e
x
+
1
)
+
C
(d) none of these
Related theory
Integration by Parts
Integration Techniques
Integrals
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