Consider the differential equation dxdy=ex. Determine whether a single particular solution can pass through both points (0,2) and (2,10).
(a) Yes, because e2≈8, so y(2)=2+8=10. (The numbers work out.)
(b) Yes, because introducing a constant of integration can always make the solution pass through any two points.
(c) No, because the particular solution through (0,2) is y=ex+1, giving y(2)≈8.39=10. (The point (2,10) is off the curve.)
(d) No, because taking y=xex+C as the antiderivative leads to y(2)≈16.8, which is greater than 10. (So the solution cannot pass through both points.)