Solve completely, for 0≤x≤2π, the trigonometric equation
2cos2x−3sinx+1=0
by proceeding as follows:
(i) Rewrite the equation entirely in terms of sinx.
(ii) Obtain and solve the resulting quadratic equation for sinx, rejecting any value that is not permissible.
(iii) For each admissible value of sinx found in part (ii), determine all corresponding values of x in the interval 0≤x≤2π.
(iv) State the complete solution set.