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A body executes SHM with spring constant and amplitude
PHYSICS · Single correct · CBSE · Physics · Oscillations · Oscillations
Problem
A body executes SHM with spring constant
k
=
80
N
m
−
1
k=80\,\text{N}\,\text{m}^{-1}
k
=
80
N
m
−
1
and amplitude
A
=
0.10
m
A=0.10\,\text{m}
A
=
0.10
m
. Determine the increase in kinetic energy when it moves from
x
1
=
0.06
m
x_1=0.06\,\text{m}
x
1
=
0.06
m
to
x
2
=
0.02
m
x_2=0.02\,\text{m}
x
2
=
0.02
m
. (a)
0.256
J
0.256\,\text{J}
0.256
J
(b)
0.064
J
0.064\,\text{J}
0.064
J
(c)
0.128
J
0.128\,\text{J}
0.128
J
(d)
0
J
0\,\text{J}
0
J
Related theory
SHM Energy
Energy in simple harmonic motion
Simple harmonic motion
Oscillations
Energy in SHM
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