Enthalpy data for the decomposition of potassium chlorate and its scaled variants are shown below.
Reaction (1): 2KClO3(s)→2KCl(s)+23O2(g)ΔH1=+89kJ
Assume standard conditions and constant external pressure.
(a) The laboratory sometimes requires only 0.50 mol of O2(g) from this decomposition. Write the balanced chemical equation that produces exactly 0.50 mol of O2(g) and state the corresponding enthalpy change ΔHa. Express ΔHa numerically and include the sign.
(b) For certain demonstrations, oxygen is instead produced by the endothermic decomposition of potassium chlorate carried out in reverse—chlorine dioxide reacts with potassium chloride to regenerate potassium chlorate. Write this reverse reaction so that it forms exactly 1.0 mol of KClO3(s), and state ΔHb. Explain in words why the magnitude of ΔHb is related to ΔH1 the way it is.
(c) Provide a short argument, based on conservation of energy, that justifies why the enthalpy change of a reaction is directly proportional to the amount (in moles) of each substance consumed or produced.