In a triangle

MATHEMATICS · Single correct · A Level · Mathematics · Trigonometry · Trigonometry

Problem

In a triangle ABCABC, tan⁡A+B2⋅cot⁡A−B2\tan\frac{A+B}{2}\cdot\cot\frac{A-B}{2} is equal to (1) a−ba+b\frac{a-b}{a+b} (2) a+bc\frac{a+b}{c} (3) a+ba−b\frac{a+b}{a-b} (4) a−b2(a+b)\frac{a-b}{2(a+b)}

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