The isotopic mass of 1840Ar is 39.962384u. The masses of a proton and a neutron are 1.007276u and 1.008665u respectively.
(a) Calculate the mass defect of an 1840Ar nucleus.
(b) Hence find its total binding energy.
(c) Determine the binding energy per nucleon and state whether 1840Ar is more or less stable than 612C whose binding energy per nucleon is 7.7MeV.
(Given: 1u=931.5MeV/c2)