Prove that the sum of the first terms of a geometric progression with first term and…

MATHEMATICS · Subjective · CBSE · Mathematics · Sequences and Series · Sequences and Series

Problem

Prove that the sum SnS_n of the first nn terms of a geometric progression with first term aa and common ratio r≠1r\neq1 is Sn=a(1−rn)1−r.S_n=\dfrac{a(1-r^{n})}{1-r}.

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